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leejunne commented at 2013-05-24 23:39:48 » #1327195

There are a total of possible combinations of two Pokemon (including themselves) of 2^649. In scientific notation, this is 2.33597 x 10^195.

This fad may last for a while.

4 Points Flag
Anonymous commented at 2013-05-25 13:33:46 » #1327479

what about the new ones? they'll probably update it

1 Points Flag
Anonymous commented at 2013-05-29 12:50:47 » #1329877

I think you're grossly overestimating that number. The number of combinations should be 649 possible choices for the first "half" of the fusion and 649 for the second "half" iff we count a pokemon with itself.

649 x 649 = 421,201 possible combinations

Better, though, is 649 possible options for the first and 648* for the second, which yields 420,552 combinations.

* The only choice removed being the repeat, as that would yield an existing pokemon (eg: Nidoking + Nidoking = Nidoking "well no shit").

5 Points Flag
leejunne commented at 2013-05-29 13:13:42 » #1329882

Ah, you're right, sorry about that.

2^n - n isn't the correct formula, because it would mean there are 1,014 combinations for 10 Pokemon, rather than the correct 90.


So it's n^2 - n. Because the generator is up to #121, Starmie, this equals 14,520 current possible combinations.

To put it into perspective, we've only scratched the surface of bizarre fusions.

0 Points Flag
CoalDragon commented at 2013-05-29 13:58:48 » #1329898

Even with n^2 - n, I imagine that fusions within the same evolutionary line would not be very impressive. A Bulbasaur fused with a Venusaur wouldn't be particularly strange to see. Even things that change drastically, such as Remoraid into Octillery, wouldn't be that striking. So I think the number is smaller still, though that's harder to get an actual formula for. You'd probably have to figure out the mean number of pokemon in an evolutionary line and include that in the formula.

0 Points Flag
Anonymous commented at 2013-06-01 22:21:45 » #1332202

looks a lot like Behemoth from Final Fantasy

2 Points Flag
Anonymous commented at 2014-05-04 12:12:19 » #1529341

Dude...... I think the formula you're looking for is n(n-1)

0 Points Flag
leejunne commented at 2014-05-04 13:56:59 » #1529373

n(n-1) IS n^2-n. n*n is n^2 and -1*n is -n.

0 Points Flag