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Anonymous commented at 2011-01-11 15:15:16 » #577891
As the change in the arc S (also known as delta S) approaches zero, the change in the velocity's direction (delta V) approaches zero as well. We therefore have (delta S)/R = (delta V)/R which means V (delta S) = R (delta V). Dividing both sides by delta t, we now have V (delta S/delta t) = R (delta V/delta t).
-Uh.... what?
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As the change in the arc S (also known as delta S) approaches zero, the change in the velocity's direction (delta V) approaches zero as well. We therefore have (delta S)/R = (delta V)/R which means V (delta S) = R (delta V). Dividing both sides by delta t, we now have V (delta S/delta t) = R (delta V/delta t).
-Uh.... what?
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